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AI悦创施工计划

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AndersonHJB...大约 3 分钟
独立博客过时后,为什么开始写博客了?

你好,我是悦创。

独立博客现在(2023)听来像是很古早的产物。独立域名、服务器空间和原创内容组成了独立博客,听起来是很 Geek 的事。独立博客设置了一道技术门栏,进门以后的人都去做技术博客了(误)。

想写一个博客是从之前就有的想法(2018),有了想法之后就有了疑惑:

  • 写博客应该写什么?
  • 我的文笔不好,写了没人看怎么办?
  • 如果我想写的东西别人已经写过了,我还有必要写吗?

抱着这样的疑惑和犹豫迟迟没有开始,直到最近读到 Alexey Guzey 的 Why you should start a Blog Right Now 才恍然大悟,鼓励了我把想法付诸实践。


AI悦创原创...大约 11 分钟
Cache Project Part 1 Main Memory

AI悦创原创...大约 3 分钟1v1java 1v1纽约大学一对一NYU 1v1web 一对一数据结构一对一留学生辅导留学生作业辅导纽约大学一对一NYU 1v1
ICS3U Unit3 Intro Java Summative Review Assignment

Answer the following questions on the pages provided. Please be as neat and clear as possible. Give full answers and show your work where asked

  1. [5 marks] Complete the truth table for the following expression: (p && q) || (!p && !q)
p q !p !q (p && q) (!p && !q) (p && q)||(!p && !q)
T T F F T F T
T F F T F F F
F T T F F F F
F F T T F T T

AI悦创原创...大约 3 分钟
Programmieren 4

AI悦创原创...大约 8 分钟python 1v1数据结构一对一留学生辅导留学生作业辅导TECHNISCHE UNIVERSITÄT
Week1:Python 基础数据类型和链表

你好,我是悦创。

我们先来看看今天要学习的内容:

  • 列表、集合、元组、字典
  • 链表

1. 你真的了解这四个数据类型吗?

  • 列表/list
  • 元组/tuple
  • 字典/dict
  • 集合/set

1.1 列表 VS. 元组

  1. 可变与不可变

  2. 选择存储策略

    a. 存储经纬度用:元组

    b. 存储用户访问:列表


AI悦创原创...大约 14 分钟数据结构与算法数据结构与算法
22-用数组灵活处理成绩

0. 目录

  • 一个程序搞定成绩的各种处理需求

1. 一个程序搞定成绩的各种处理需求

  • 求某年最好成绩
  • 求某年的平均成绩
  • 求所有年份最好成绩
  • 求某门课历年最好成绩
  • 自由发挥……
/**
 * @ClassName: ScoreMaster
 * @Description: TODO
 * @Author: AI悦创
 * @Date: 2022/10/9 19:24
 * @Version: V1.0
 * @Blog: https://www.bornforthis.cn
 */

import java.util.Scanner;

public class ScoreMaster {
    public static void main(String[] args) {

        // 声明六个变量, 分别代表六门科目的成绩
        int YuWenIndex = 0;
        int ShuXueIndex = 1;
        int WaiYuIndex = 2;
        int WuLiIndex = 3;
        int HuaXueIndex = 4;
        int ShengWuIndex = 5;

        int totalScoreCount = 6;

        // 每门课的名字
        String[] names = new String[totalScoreCount];
        names[YuWenIndex] = "语文";
        names[ShuXueIndex] = "数学";
        names[WaiYuIndex] = "外语";
        names[WuLiIndex] = "物理";
        names[HuaXueIndex] = "化学";
        names[ShengWuIndex] = "生物";

        Scanner scanner = new Scanner(System.in);

        System.out.println("请输入共有多少年的成绩:");

        int yearCount = scanner.nextInt();

        double[][] scores = new double[yearCount][totalScoreCount];  // 看几年的数组

        for (int i = 0; i < yearCount; i++) {
            for (int j = 0; j < totalScoreCount; j++) {
                scores[i][j] = 80 + Math.random() * 20;
                System.out.println("第" + (i + 1) + "年" + names[j] + "成绩为:" + scores[i][j]);
            }
        }

        boolean cont = true;
        while (cont) {
            System.out.println("请选择要进行的操作:");
            System.out.println("1: 求某年最好成绩\n" +
                    "2: 求某年的平均成绩\n" +
                    "3: 求所有年份最好成绩\n" +
                    "4: 求某门课历年最好成绩");

            int oprtId = scanner.nextInt();

            int year = 0;  // 在 switch 用一块代码块里,不能声明同一个变量,所以直接写在外面,方便。不然得想不同的变量名。
            switch (oprtId) {
                // 先编写 case
                case 1:
                    // 让用户输入指定的年份
                    System.out.println("请输入要计算第几年的最好成绩");
                    year = scanner.nextInt();
                    if (year <= 0 || yearCount < year) {
                        System.out.println("非法的年份:" + year);
                        cont = false;
                        break;
                    }
                    year = year - 1;
                    // 指定年份的最好成绩的编号,开始假设是0
                    int bestOfYearScoreId = 0;
                    // 循环指定年份的成绩,找出最好的成绩
                    // TODO:如果有两门课的成绩一样,而且都是最高的,怎么办?
                    for (int i = 1; i < totalScoreCount; i++) {
                        if (scores[year][bestOfYearScoreId] < scores[year][i]) {
                            bestOfYearScoreId = i;
                        }
                    }
                    System.out.println("第" + (year + 1) + "年成绩最好的科目为" + names[bestOfYearScoreId] + ",成绩为" + scores[year][bestOfYearScoreId] + "。");
                    break;
                case 2:
                    System.out.println("请输入要计算第几年的平均成绩");
                    year = scanner.nextInt();
                    if (year <= 0 || yearCount < year) {
                        System.out.println("非法的年份:" + year);
                        cont = false;
                        break;
                    }
                    year = year - 1;
                    double totalCountForAvg = 0;
                    for (int i = 0; i < totalScoreCount; i++) {
                        totalCountForAvg += scores[year][i];
                    }
                    double avgOfYear = totalCountForAvg / totalScoreCount;
                    System.out.println("第" + (year + 1) + "年的平均成绩为" + avgOfYear + "。");
                    break;
                case 3:
                    int bestYear = 0;
                    int bestScore = 0;

                    for (int i = 0; i < yearCount; i++) {
                        for (int j = 0; j < totalScoreCount; j++) {
                            if (scores[bestYear][bestScore] < scores[i][j]) {
                                bestYear = i;
                                bestScore = j;
                            }
                        }
                    }
                    // 视频中代码有错误,应该是使用 bestYear 而不是 year, 鸣谢 @zZGod 帮忙揪出 bug 一只。
                    System.out.println("所有年度最好成绩为第" + (bestYear + 1) + "年的" + names[bestScore] + ",成绩为" + scores[bestYear][bestScore] + "。");
                    break;
                case 4:
                    System.out.println("请输入科目编号");
                    int subjectId = scanner.nextInt();
                    if (subjectId <= 0 || totalScoreCount < subjectId) {
                        System.out.println("非法的科目编号:" + subjectId);
                        cont = false;
                        break;
                    }
                    subjectId = subjectId - 1;
                    year = 0;
                    for (int i = 1; i < yearCount; i++) {
                        if (scores[year][subjectId] < scores[i][subjectId]) {
                            year = i;
                        }
                    }
                    System.out.println("第" + (year + 1) + "年度" + names[subjectId] + "成绩最好,为" + scores[year][subjectId] + "。");

                    break;
                default:
                    cont = false;
                    System.out.println("不支持:" + oprtId + ", 程序结束。");
            }
        }

    }
}

AI悦创原创...大约 10 分钟Java体系课Java体系课
21-多维数组

0. 目录

  • 如果要存储多年的成绩怎么办?
  • 多维数组
  • 用多维数组存储多年的成绩

1. 如果要存储多年的成绩怎么办?

  • 为每年创建一个数组?
  • 这种行为和为每一门成绩创建一个变量很像!
import java.util.Scanner;

public class OneYearOneArray {
    public static void main(String[] args) {
        // 声明六个变量, 分别代表六门科目的成绩
        int YuWenIndex = 0;
        int ShuXueIndex = 1;
        int WaiYuIndex = 2;
        int WuLiIndex = 3;
        int HuaXueIndex = 4;
        int ShengWuIndex = 5;

        // 每门课的名字
        String[] names = new String[6];
        names[YuWenIndex] = "语文";
        names[ShuXueIndex] = "数学";
        names[WaiYuIndex] = "外语";
        names[WuLiIndex] = "物理";
        names[HuaXueIndex] = "化学";
        names[ShengWuIndex] = "生物";

        // 每门课的成绩
        double[] year1 = new double[6];

        // 用随机数给成绩赋值
        for (int i = 0; i < 6; i++) {
            year1[i] = 80 + Math.random() * 20;
        }

        // 每门课的成绩
        double[] year2 = new double[6];

        // 用随机数给成绩赋值
        for (int i = 0; i < 6; i++) {
            year2[i] = 80 + Math.random() * 20;
        }

        // 每门课的成绩
        double[] year3 = new double[6];

        // 用随机数给成绩赋值
        for (int i = 0; i < 6; i++) {
            year3[i] = 80 + Math.random() * 20;
        }

        double[] yearToUse;

        Scanner scanner = new Scanner(System.in);
        System.out.println("请输入要查看第几年的成绩:");
        int year = scanner.nextInt();

        switch (year) {
            case 1:
                yearToUse = year1;
                break;
            case 2:
                yearToUse = year2;
                break;
            case 3:
                yearToUse = year3;
                break;
            default:
                System.out.println("输入的年份不对,将查看的是最新一年的成绩");
                yearToUse = year3;
                break;

        }

        System.out.println("请输入要查看的成绩编号:");

        int scoreIndex = scanner.nextInt();

        System.out.println("第" + year + "年的" + names[scoreIndex] + "的成绩是:" + yearToUse[scoreIndex]);

    }
}

AI悦创原创...大约 4 分钟Java体系课Java体系课
20-认识变量和数组

0. 目录

  • 重新认识基本类型的变量
  • 认识数组
  • 数组的长度
  • 数组索引过界会出错
  • 让变量代表新的数组

1. 重新认识基本类型的变量

1.1 一个简单的使用变量的程序

import java.util.Scanner;

public class UseVariable {
    public static void main(String[] args) {
        Scanner in = new Scanner(System.in);

        int a;
        System.out.println("创建了变量 a,输入一个整数:");
        a = in.nextInt();
        System.out.println("给 a 赋值,a 的值为" + a + ",请再次输入一个整数:");

        a = in.nextInt();
        System.out.println("再次给赋值,现在 a 的值为" + a);
    }
}

AI悦创原创...大约 8 分钟Java体系课Java体系课
19-用数组保存成绩

0. 目录

  • 语数外物化生的成绩怎么表示?
  • 什么是数组和数组的语法
  • 用数组处理 6 门课的成绩

1. 语数外物化生的成绩怎么表示?

  • 用六个变量表示,如果有更多的科目怎么办?
  • 如果有更多的科目怎么办?
  • 如果想求出成绩最高的科目怎么办?
public class SevenScore {
    public static void main(String[] args) {
        // 声明六个变量, 分别代表六门科目的成绩
        int YuWen = 0;
        int ShuXue = 0;
        int WaiYu = 0;
        int WuLi = 0;
        int HuaXue = 0;
        int ShengWu = 0;
    }
}

AI悦创原创...大约 4 分钟Java体系课Java体系课
AIGC一对一教学课程计划

Midjourney

序号 名称
第一章 Midjourney
01 Midjourney 注册及订阅详细流程

AI悦创原创...大约 1 分钟Python 基础Python一对一教学Python 基础Python一对一教学
Use a Squarespace domain with GitHub Pages

Hello, I'm Yue Chuang.

Creating your website with a custom URL is momentous. Your first entrance into fashionable Internet society. A digital debutante ball. A modern promenade. Many of us haven’t staked a claim like this since joining the AIM community behind a clever screen name.

This tutorial will teach you how to publish your website directly from GitHub to a Squarespace domain. GitHub also has a Managing a custom domain for your GitHub Pages site document with helpful instructions.


AI悦创原创...大约 3 分钟小技巧小技巧
Math 1MP3 * Assignment 3

Given two dictionaries d1 and d2, create a new dictionary d3 according to the fol-lowing rule (think of transitivity): the entry a:c is in d3 if and only if there is an entry a:b in d1, and an entry b:c in d2.


AI悦创原创...大约 2 分钟
第五封信|我的计划

AI悦创原创...小于 1 分钟悦创来信·去无方向的信心灵咖啡馆精神健康自我提升松弛工作
Assignment 3
  1. [2] Write a function spell_number(n) where n is an integer between 1 and 9999. Out-put is that number spelled out in words. So, spell_number(821) prints eight hundred twenty one, and spell_number(3017) prints three thousand seventeen.
#Question 1 

def spell_number(n):
    """ spell a given integer between 1 and 9999
    """
    
    
    
    
    
print(spell_number(9307)) # should print nine thousand three hundred seven
print(spell_number(5004)) # should print five thousand four
print(spell_number(1616)) # should print one thousand six hundred sixteen
print(spell_number(13)) # should print thirteen
print(spell_number(906)) # should print nine hundred six
print(spell_number(67)) # should print sixty seven
print(spell_number(632)) # should print six hundred thirty two
print(spell_number(2)) # should print two
print(spell_number(111)) # should print one hundred eleven

AI悦创原创...大约 7 分钟