Homework
原创2023年10月24日大约 2 分钟...约 474 字
- Modify the condition in the outer loop so the turtle drawing has two “peaks” as shown, instead of one. No other change to the code needs to be made.
# a114_nested_loops_4.py
import time
import turtle as trtl
painter = trtl.Turtle()
painter.penup()
painter.goto(-200, 0)
painter.pendown()
x = -200
y = 0
move_x = 1
move_y = 1
while x < 200:
while y < 100:
x = x + move_x
y = y + move_y
painter.goto(x, y)
move_y = -1
while y > 0:
x = x + move_x
y = y + move_y
painter.goto(x, y)
move_y = 1
# print("dd")
# time.sleep(10)
x = -200
y = 0
move_x = 1
move_y = -1 # 初始y方向改为向下
painter.penup()
painter.goto(-200, 0)
painter.pendown()
while x < 200:
while y > -100: # 变为负值
x = x + move_x
y = y + move_y
print("上:", x, y)
painter.goto(x, y)
move_y = 1 # 现在向上移动
while y < 0:
x = x + move_x
y = y + move_y
print("下:", x, y)
painter.goto(x, y)
move_y = -1 # 恢复向下的方向
wn = trtl.Screen()
wn.mainloop()
Add Window Input using wn.textinput() and wn.numinput() screenshot code and window.
i = int(input("enter number:"))
while (i >= 0):
i = i + 1
print(i)
公众号:AI悦创【二维码】
AI悦创·编程一对一
AI悦创·推出辅导班啦,包括「Python 语言辅导班、C++ 辅导班、java 辅导班、算法/数据结构辅导班、少儿编程、pygame 游戏开发、Web、Linux」,全部都是一对一教学:一对一辅导 + 一对一答疑 + 布置作业 + 项目实践等。当然,还有线下线上摄影课程、Photoshop、Premiere 一对一教学、QQ、微信在线,随时响应!微信:Jiabcdefh
C++ 信息奥赛题解,长期更新!长期招收一对一中小学信息奥赛集训,莆田、厦门地区有机会线下上门,其他地区线上。微信:Jiabcdefh
方法一:QQ
方法二:微信:Jiabcdefh
你认为这篇文章怎么样?
- 0
- 0
- 0
- 0
- 0
- 0