Math 1MP3 * Assignment 3

Given two dictionaries d1 and d2, create a new dictionary d3 according to the fol-lowing rule (think of transitivity): the entry a:c is in d3 if and only if there is an entry a:b in d1, and an entry b:c in d2.

Forinstance: if d1={2: 3,8: 19,6: 4,5: 3} and d2={2: 5,4: 3,3: 9} your code should create the dictionary d3={2 : 9, 6 : 3, 5 : 9}.

#Question 5

def transitive_dict(d1,d2):
    """ create a dictionary by transitivity
    """
  



    
print(transitive_dict({2:3, 8:19, 6:4, 5:3},{2:5, 4:3, 3:9}))  #should return {2: 9, 6: 3, 5: 9}
print(transitive_dict({2:3, 6:4, 5:3},{2:5, 6:9}))  #should return empty dictionary  
print(transitive_dict({2:3, 3:3, 4:3},{3:2, 5:3, 6:9}))  #should return {2: 2, 3: 2, 4: 2}

创建一个函数 opt_num，获取用户输入 num1 和 num2，num1 和 num2 分别为列表，用户必须传入参数 num1，num2 参数传入可选（可以传入也可以不传入，num2 默认 [1, 2, 3, 4]。得到结果为两个列表内部各个元素平方之后的拼接。

[1, 2, 3] [3, 4, 5]

[1, 4, 9, 9, 16, 25]

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